Calculates the frequency table with respect to the open left boundary convention for YValues of the series.
[Visual Basic]
Overloads Public Shared Function FrequencyTableOL( _
   ByVal s As Series, _
   ByVal boundaries() As Double _
) As Series[C#]
public static Series FrequencyTableOL( 
   Series s,
   double[] boundaries
);
            Say for example the boundary points used are {b_1, b_2, ..., b_n},
            now the first term of the array returned which represents the frequency table, is the
            number of elements from the data set within the interval (-infinity, b_1),
            the second term of the array returned is the number of elements from the data set within
            the interval [b_1, b_2), and so on...
             
            
Consider the set of boundaries { 1, 2, 3, 4, 5 }, which divide the real
            line into six sub-intervals. Now if we use the open left boundary convention then the
            real line will be divided into the sub-intervals:
	
            (-infinity, 1], (1,2], (2,3], (3,4], (4,5], (5, infinity)
	
            Note that, each point on the real line can be assigned to one of these sub-intervals
            and therefore when assigning a data point to one of these intervals there will only
            be one sub-interval in which it belongs.
Therefore, if we consider the data set { 0.5, 1.4, 1.3, 2.0, 2.3, 4.5, 5.5},
            if the assign this data set in accordance with the above the conventions then we will
            have: using Open Left Boundary (OLB) convention:
            
(-infinity, 1], we assign the data element 0.5;
            and hence the frequency of this interval is 1.
            (1, 2], we assign the data element 1.4, 1.3, 2.0;
            and hence the frequency of this interval (wrt OLB convention) is 3.
            (2, 3], we assign the data element 2.3, and hence
            the frequency of this interval (wrt OLB convention) is 1.
            (3, 4], we assign no data elements, and hence the frequency of
            this interval (wrt OLB convention) is 0.
            (4, 5], we assign the data element 4.5, and hence
            the frequency of this interval (wrt OLB convention) is 1.
            (5, infinity), we assign the data element 5.5, and
            hence the frequency of this interval (wrt OLB convention) is 1.
            Hence, in this case the series returned corresponding to the frequency table will be
            {1, 3, 1, 0, 1, 1}.
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